Last_Index_of_Number.cpp

/*
Problem:
Given an array of length N and an integer x, you need to find and return the last index of integer x present in the array. Return -1 if it is not present in the array.
Last index means - if x is present multiple times in the array, return the index at which x comes last in the array.
You should start traversing your array from 0, not from (N - 1).
Do this recursively. Indexing in the array starts from 0.
Input Format :
Line 1 : An Integer N i.e. size of array
Line 2 : N integers which are elements of the array, separated by spaces
Line 3 : Integer x
Output Format :
last index or -1
Constraints :
1 <= N <= 10^3
Sample Input :
4
9 8 10 8
8
Sample Output :
3
CODE:
*/

int lastIndex(int input[], int size, int x) {
int index=0;
 for(int i=0;i<size;i++){
     
    if(input[i]==x){
        index=i;
         for(int j=i;j<size;j++){
        if(input[j]==x){index=j;}
        
       
         }
         return index;
      }
 }
return -1;
}