even numbers in circular linked list

#include <stdio.h>
#include <stdlib.h>

struct node{
	int element;
	struct node* p;
};

void print(struct node* ref)
{
	struct node *temp = ref;
	if (ref != NULL)
	{
		do
		{
			printf("%d", temp->element);
			temp = temp->p;
		}
		while (temp != ref);
	}
	printf("\n");
}

void insert_node(struct node** ref, int new_element)
{
	struct node* New = (struct node*)malloc(sizeof(struct node));
	struct node* temp = *ref;
	New->element = new_element;
	New->p = *ref;
	if (*ref != NULL)
	{
		while (temp->p != *ref)
			temp = temp->p;
		temp->p = New;
	}
	else
		New->p = New;
	*ref = New;
}

int sum_even(struct node* ref)
{
	int sum = 0, i;
	struct node* temp = ref;
	if (ref != NULL)
	{
		do
		{
			temp = temp->p;
			i = temp->element;
			if (i%2 == 0)
			{
				sum = sum + i;
			}
		}
		while (temp != ref);
	}
	return sum;
}

int main()
{
	int i, element;
	printf("Sum of even numbers in the linked list is\n");
	printf("Enter 10 integers to the linked list:\n");
	struct node *s = NULL;
	for(i=0; i<10; i++)
	{
		printf("Number %d: ", i+1);
		scanf("%d", &element);
		insert_node(&s, element);
	}
	printf("Elements in the circular linked list are \n ");
	print(s);
	printf("Sum of the even numbers is %d\n", sum_even(s));
	return 0;
}