Working on a project recently, which requires generating random secured passwords for users, sounds simple? Yeah, me too, I quickly rolled out my first version, a random password generator, then found out not happy with how to control password length, how many uppercases, digitals, symbols apply in a password. Worked out the second version, guess what? Not happy again, with some char sets like, o 0 O, I 1 l, which are a bit visually aggressive in password. Also some applications accept limited symbols.
So I did a bit of research on this topic, a heap of libraries available there, but either too complex to configure or too simple like my old one.
Coding a library for the community? Let's do it....then, I realized that I have to refactor my code, because you don't want to present you sh*t code to the public. In a library, every line of code should be accountable and elegant. Not mention that you need to have a good comprehensive document with examples. And version control, change log , setup, deployment are all must. A lot of work ahead.
based on Perfect Paper Passwords
High security multifactor authentication password generator.
This is the standard and conservative PPP set of 64 characters. It was chosen to remove characters that might be confused with one another. Using 4-characters per passcode, 16,777,216 passcodes are possible for very good one time password security
passcode_set = '!#%+23456789=?@ABCDEFGHJKLMNPRSTUVWXYZabcdefghijkmnopqrstuvwxyz'
use standard set to create password length = 10, with 3 uppercases, 3 digits and 1 symbol
from pyPasswordGenerator import password as ps
# standard set
set = 's'
ps.generator(length = 10, upper = 3, digits =3, symbol = 0, set =set )
>>>'5v5njx9BAN'
This is a much more "visually aggressive" (somewhat more interesting and certainly much stronger) 88-character alphabet which supports the generation of 59,969,536 possible 4-character passcodes:
passcode_set = '''!"#$%&'()*+,-./23456789:;<=>?@ABCDEFGHJKLMNOPRSTUVWXYZ[]^_abcdefghijkmnopqrstuvwxyz{|}~'''
use standard set to create password length = 8, with 2 uppercases, 2 digits and 2 symbol
from pyPasswordGenerator import password as ps
# visually aggressive set
set = 'v'
ps.generator(length = 8, upper = 2, digits =2, symbol = 2, set =set )
>>>'sX65%A^g'
use won set to limit symbol with only !#@
from pyPasswordGenerator import password as ps
# my own password set
set = '!#23456789@ABCDEFGHJKLMNPRSTUVWXYZabcdefghijkmnopqrstuvwxyz'
ps.generator(length = 11, upper = 4, digits =2, symbol = 2, set =set )
>>>'@F8Wa#jRn6S'
| Parameter | Default | Description |
|---|---|---|
| length | 8 | Length of Password, if length = 10 then xdat3a9$dg |
| upper | 2 | How many upper case charactors, if upper =4 GdAT3a9$Dg |
| digits | 2 | How many digits, if digits = 1 GdAT3ad$Dg |
| symbol | 0 | How many symbol if symbol=4 G#A!3a9$D! |
| passcode_set | s | v |
pip install pyPasswordGenerator