Determine if a 9 x 9
Sudoku board is valid. Only the filled cells need to be validated according to the following rules:
- Each row must contain the digits
1-9
without repetition. - Each column must contain the digits
1-9
without repetition. - Each of the nine
3 x 3
sub-boxes of the grid must contain the digits1-9
without repetition.
Note:
- A Sudoku board (partially filled) could be valid but is not necessarily solvable.
- Only the filled cells need to be validated according to the mentioned rules.
Example 1:
Input: board = [["5","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] Output: true
Example 2:
Input: board = [["8","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] Output: false Explanation: Same as Example 1, except with the 5 in the top left corner being modified to 8. Since there are two 8's in the top left 3x3 sub-box, it is invalid.
Constraints:
board.length == 9
board[i].length == 9
board[i][j]
is a digit or'.'
.
class Solution:
def isValidSudoku(self, board: List[List[str]]) -> bool:
row = [[False] * 9 for _ in range(9)]
col = [[False] * 9 for _ in range(9)]
sub = [[False] * 9 for _ in range(9)]
for i in range(9):
for j in range(9):
c = board[i][j]
if c == '.':
continue
num = int(c) - 1
k = i // 3 * 3 + j // 3
if row[i][num] or col[j][num] or sub[k][num]:
return False
row[i][num] = True
col[j][num] = True
sub[k][num] = True
return True
class Solution {
public boolean isValidSudoku(char[][] board) {
boolean[][] row = new boolean[9][9];
boolean[][] col = new boolean[9][9];
boolean[][] sub = new boolean[9][9];
for (int i = 0; i < 9; ++i) {
for (int j = 0; j < 9; ++j) {
char c = board[i][j];
if (c == '.') {
continue;
}
int num = c - '0' - 1;
int k = i / 3 * 3 + j / 3;
if (row[i][num] || col[j][num] || sub[k][num]) {
return false;
}
row[i][num] = true;
col[j][num] = true;
sub[k][num] = true;
}
}
return true;
}
}
class Solution {
public:
bool isValidSudoku(vector<vector<char>>& board) {
vector<vector<bool>> row(9, vector<bool>(9, false));
vector<vector<bool>> col(9, vector<bool>(9, false));
vector<vector<bool>> sub(9, vector<bool>(9, false));
for (int i = 0; i < 9; ++i) {
for (int j = 0; j < 9; ++j) {
char c = board[i][j];
if (c == '.') continue;
int num = c - '0' - 1;
int k = i / 3 * 3 + j / 3;
if (row[i][num] || col[j][num] || sub[k][num]) {
return false;
}
row[i][num] = true;
col[j][num] = true;
sub[k][num] = true;
}
}
return true;
}
};
func isValidSudoku(board [][]byte) bool {
row, col, sub := [9][9]bool{}, [9][9]bool{}, [9][9]bool{}
for i := 0; i < 9; i++ {
for j := 0; j < 9; j++ {
num := board[i][j] - byte('1')
if num < 0 || num > 9 {
continue
}
k := i/3*3 + j/3
if row[i][num] || col[j][num] || sub[k][num] {
return false
}
row[i][num] = true
col[j][num] = true
sub[k][num] = true
}
}
return true
}
/**
* @param {character[][]} board
* @return {boolean}
*/
var isValidSudoku = function(board) {
let row = [...Array(9)].map(() => Array(9).fill(false));
let col = [...Array(9)].map(() => Array(9).fill(false));
let sub = [...Array(9)].map(() => Array(9).fill(false));
for (let i = 0; i < 9; ++i) {
for (let j = 0; j < 9; ++j) {
const num = board[i][j].charCodeAt() - '1'.charCodeAt();
if (num < 0 || num > 9) {
continue;
}
const k = Math.floor(i / 3) * 3 + Math.floor(j / 3);
if (row[i][num] || col[j][num] || sub[k][num]) {
return false;
}
row[i][num] = true;
col[j][num] = true;
sub[k][num] = true;
}
}
return true;
};