README_EN.md

227. Basic Calculator II

中文文档

Description

Given a string s which represents an expression, evaluate this expression and return its value. 

The integer division should truncate toward zero.

 

Example 1:

Input: s = "3+2*2"
Output: 7

Example 2:

Input: s = " 3/2 "
Output: 1

Example 3:

Input: s = " 3+5 / 2 "
Output: 5

 

Constraints:

• 1 <= s.length <= 3 * 105
• s consists of integers and operators ('+', '-', '*', '/') separated by some number of spaces.
• s represents a valid expression.
• All the integers in the expression are non-negative integers in the range [0, 231 - 1].
• The answer is guaranteed to fit in a 32-bit integer.

Solutions

Python3

class Solution:
    def calculate(self, s: str) -> int:
        num, n = 0, len(s)
        pre_sign = '+'
        stack = []
        for i in range(n):
            if s[i].isdigit():
                num = num * 10 + int(s[i])
            if i == n - 1 or (not s[i].isdigit() and s[i] != ' '):
                if pre_sign == '+':
                    stack.append(num)
                elif pre_sign == '-':
                    stack.append(-num)
                elif pre_sign == '*':
                    stack.append(stack.pop() * num)
                else:
                    stack.append(int(stack.pop() / num))
                pre_sign = s[i]
                num = 0
        res = 0
        while stack:
            res += stack.pop()
        return res

Java

class Solution {
    public int calculate(String s) {
        int num = 0;
        char preSign = '+';
        Deque<Integer> stack = new ArrayDeque<>();
        for (int i = 0, n = s.length(); i < n; ++i) {
            if (Character.isDigit(s.charAt(i))) {
                num = num * 10 + (s.charAt(i) - '0');
            }
            if (i == n - 1 || (!Character.isDigit(s.charAt(i)) && s.charAt(i) != ' ')) {
                switch (preSign) {
                    case '+':
                        stack.push(num);
                        break;
                    case '-':
                        stack.push(-num);
                        break;
                    case '*':
                        stack.push(stack.pop() * num);
                        break;
                    case '/':
                        stack.push(stack.pop() / num);
                        break;
                }
                preSign = s.charAt(i);
                num = 0;
            }
        }

        int res = 0;
        while (!stack.isEmpty()) {
            res += stack.pop();
        }
        return res;
    }
}

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