You are given an integer array coins
of length n
which represents the n
coins that you own. The value of the ith
coin is coins[i]
. You can make some value x
if you can choose some of your n
coins such that their values sum up to x
.
Return the maximum number of consecutive integer values that you can make with your coins starting from and including 0
.
Note that you may have multiple coins of the same value.
Example 1:
Input: coins = [1,3] Output: 2 Explanation: You can make the following values: - 0: take [] - 1: take [1] You can make 2 consecutive integer values starting from 0.
Example 2:
Input: coins = [1,1,1,4] Output: 8 Explanation: You can make the following values: - 0: take [] - 1: take [1] - 2: take [1,1] - 3: take [1,1,1] - 4: take [4] - 5: take [4,1] - 6: take [4,1,1] - 7: take [4,1,1,1] You can make 8 consecutive integer values starting from 0.
Example 3:
Input: nums = [1,4,10,3,1] Output: 20
Constraints:
coins.length == n
1 <= n <= 4 * 104
1 <= coins[i] <= 4 * 104
class Solution:
def getMaximumConsecutive(self, coins: List[int]) -> int:
res = 1
for coin in sorted(coins):
if coin > res:
break
res += coin
return res
class Solution {
public int getMaximumConsecutive(int[] coins) {
int res = 1;
Arrays.sort(coins);
for (int coin : coins) {
if (coin > res) {
break;
}
res += coin;
}
return res;
}
}