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Parent Child Relationship Query
中文 | English
无限级分类(父子)是一种比较常用的表设计,每种设计方式突出优势的同时也带来缺陷,如:
- 方法1:表设计中只有 parent_id 字段,困扰:查询麻烦(本文可解决);
- 方法2:表设计中冗余子级id便于查询,困扰:添加/更新/删除的时候需要重新计算;
- 方法3:表设计中存储左右值编码,困扰:同上;
方法1设计最简单,本文解决它的递归查询问题,让使用透明化。
FreeSql 导航属性之中,有针对父子关系的设置方式,如下:
public class Area
{
[Column(IsPrimary = true)]
public string Code { get; set; }
public string Name { get; set; }
public string ParentCode { get; set; }
[Navigate(nameof(ParentCode))]
public Area Parent { get; set; }
[Navigate(nameof(ParentCode))]
public List<Area> Childs { get; set; }
}
定义 Parent 属性,在表达式中可以这样:
fsql.Select<Area>().Where(a => a.Parent.Parent.Parent.Name == "中国").First();
定义 Childs 属性,在表达式中可以这样(子查询):
fsql.Select<Area>().Where(a => a.Childs.AsSelect().Any(c => c.Name == "北京")).First();
定义 Childs 属性,还可以使用【级联保存】、【贪婪加载】 等等操作。
fsql.Delete<Area>().Where("1=1").ExecuteAffrows();
var repo = fsql.GetRepository<Area>();
repo.DbContextOptions.EnableAddOrUpdateNavigateList = true;
repo.DbContextOptions.NoneParameter = true;
repo.Insert(new Area
{
Code = "100000",
Name = "中国",
Childs = new List<Area>(new[] {
new Area
{
Code = "110000",
Name = "北京",
Childs = new List<Area>(new[] {
new Area{ Code="110100", Name = "北京市" },
new Area{ Code="110101", Name = "东城区" },
})
}
})
});
配置好父子属性之后,就可以这样用了:
var t1 = fsql.Select<Area>().ToTreeList();
Assert.Single(t1);
Assert.Equal("100000", t1[0].Code);
Assert.Single(t1[0].Childs);
Assert.Equal("110000", t1[0].Childs[0].Code);
Assert.Equal(2, t1[0].Childs[0].Childs.Count);
Assert.Equal("110100", t1[0].Childs[0].Childs[0].Code);
Assert.Equal("110101", t1[0].Childs[0].Childs[1].Code);
查询数据本来是平面的,ToTreeList 方法将返回的平面数据在内存中加工为树型 List 返回。
Very common infinite level classification table function, when deleting a tree node, the child nodes are also processed.
fsql.Select<Area>()
.Where(a => a.Name == "中国")
.AsTreeCte()
.ToDelete()
.ExecuteAffrows(); //Delete all records under 中国.
If logically delete:
fsql.Select<Area>()
.Where(a => a.Name == "中国")
.AsTreeCte()
.ToUpdate()
.Set(a => a.IsDeleted, true)
.ExecuteAffrows(); //Logically delete all records under 中国.
If you do not design an infinite level classification table with data redundancy, recursive query is essential. AsTreeCte
is the package for solving recursive query. Method parameters description:
Parameter | Description |
---|---|
(Optional) pathSelector | 路径内容选择,可以设置查询返回:中国 -> 北京 -> 东城区 |
(Optional) up | false(默认):由父级向子级的递归查询,true:由子级向父级的递归查询 |
(Optional) pathSeparator | 设置 pathSelector 的连接符,默认:-> |
(Optional) level | 设置递归层级 |
Databases that have passed the test: MySql8.0, SqlServer, PostgreSQL, Oracle, Sqlite, Firebird, 达梦, 人大金仓 and 翰高.
Practice 1: AsTreeCte() + ToTreeList
var t2 = fsql.Select<Area>()
.Where(a => a.Name == "中国")
.AsTreeCte() //Query all records under 中国
.OrderBy(a => a.Code)
.ToTreeList(); //Not necessary, you can also use ToList (see Practice 2)
Assert.Single(t2);
Assert.Equal("100000", t2[0].Code);
Assert.Single(t2[0].Childs);
Assert.Equal("110000", t2[0].Childs[0].Code);
Assert.Equal(2, t2[0].Childs[0].Childs.Count);
Assert.Equal("110100", t2[0].Childs[0].Childs[0].Code);
Assert.Equal("110101", t2[0].Childs[0].Childs[1].Code);
// WITH "as_tree_cte"
// as
// (
// SELECT 0 as cte_level, a."Code", a."Name", a."ParentCode"
// FROM "Area" a
// WHERE (a."Name" = '中国')
// union all
// SELECT wct1.cte_level + 1 as cte_level, wct2."Code", wct2."Name", wct2."ParentCode"
// FROM "as_tree_cte" wct1
// INNER JOIN "Area" wct2 ON wct2."ParentCode" = wct1."Code"
// )
// SELECT a."Code", a."Name", a."ParentCode"
// FROM "as_tree_cte" a
// ORDER BY a."Code"
Practice 2: AsTreeCte() + ToList
var t3 = fsql.Select<Area>()
.Where(a => a.Name == "中国")
.AsTreeCte()
.OrderBy(a => a.Code)
.ToList();
Assert.Equal(4, t3.Count);
Assert.Equal("100000", t3[0].Code);
Assert.Equal("110000", t3[1].Code);
Assert.Equal("110100", t3[2].Code);
Assert.Equal("110101", t3[3].Code);
//The executed SQL is the same as Practice 1
Practice 3: AsTreeCte(pathSelector) + ToList
After setting the pathSelector
parameter, how to return the hidden field?
var t4 = fsql.Select<Area>()
.Where(a => a.Name == "中国")
.AsTreeCte(a => a.Name + "[" + a.Code + "]")
.OrderBy(a => a.Code)
.ToList(a => new {
item = a,
level = Convert.ToInt32("a.cte_level"),
path = "a.cte_path"
});
Assert.Equal(4, t4.Count);
Assert.Equal("100000", t4[0].item.Code);
Assert.Equal("110000", t4[1].item.Code);
Assert.Equal("110100", t4[2].item.Code);
Assert.Equal("110101", t4[3].item.Code);
Assert.Equal("中国[100000]", t4[0].path);
Assert.Equal("中国[100000] -> 北京[110000]", t4[1].path);
Assert.Equal("中国[100000] -> 北京[110000] -> 北京市[110100]", t4[2].path);
Assert.Equal("中国[100000] -> 北京[110000] -> 东城区[110101]", t4[3].path);
// WITH "as_tree_cte"
// as
// (
// SELECT 0 as cte_level, a."Name" || '[' || a."Code" || ']' as cte_path, a."Code", a."Name", a."ParentCode"
// FROM "Area" a
// WHERE (a."Name" = '中国')
// union all
// SELECT wct1.cte_level + 1 as cte_level, wct1.cte_path || ' -> ' || wct2."Name" || '[' || wct2."Code" || ']' as cte_path, wct2."Code", wct2."Name", wct2."ParentCode"
// FROM "as_tree_cte" wct1
// INNER JOIN "Area" wct2 ON wct2."ParentCode" = wct1."Code"
// )
// SELECT a."Code" as1, a."Name" as2, a."ParentCode" as5, a.cte_level as6, a.cte_path as7
// FROM "as_tree_cte" a
// ORDER BY a."Code"
More practice...please try according to the code comments.