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Filterizr version Latest !
Describe the issue in details Hello everyone
How can i filter a menu items, directly from pasting url on browser.
for example ... web.com/portfolio?category_id=2
and get directly , items of category 2 filtered on fileterizr menu.
is this possible , how can i do this ?
I have my menu like this.
<div class="container"> <div class="row"> <div class="col-12"> <div class="portfolio-menu"> <ul id="filtrnav"> <li class="filtr filtr-active" data-filter="all"><?php echo ALL; ?></li> <?php foreach ($portfolio_category as $row) { ?> <li class="filtr" data-filter="<?php echo $row['category_id']; ?>" id="<?php echo $row['category_id']; ?>"><?php echo $row['category_name']; ?></li> <?php } ?> </ul> </div> </div> </div> <div class="row filtr-container"> <?php foreach ($portfolio as $row) { ?> <div class="col-lg-4 col-md-6 filtr-item" data-category="<?php echo $row['category_id']; ?>" data-sort="Menu"> <div class="portfolio-group"> <div class="portfolio-photo" style="background-image: url(<?php echo base_url(); ?>public/uploads/<?php echo $row['photo']; ?>)"> <div class="portfolio-bg"></div> <div class="portfolio-table"> <div class="portfolio-icon"> <a href="<?php echo base_url(); ?>public/uploads/<?php echo $row['photo']; ?>" class="magnific"><i class="fa fa-search-plus"></i></a> </div> </div> </div> <div class="portfolio-text"> <h3><a href="<?php echo base_url(); ?>portfolio/view/<?php echo $row['id']; ?>"><?php echo $row['name']; ?></a></h3> </div> </div> </div> <?php } ?> </div>
The text was updated successfully, but these errors were encountered:
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Filterizr version
Latest !
Describe the issue in details
Hello everyone
How can i filter a menu items, directly from pasting url on browser.
for example ... web.com/portfolio?category_id=2
and get directly , items of category 2 filtered on fileterizr menu.
is this possible , how can i do this ?
I have my menu like this.
The text was updated successfully, but these errors were encountered: