We read every piece of feedback, and take your input very seriously.
To see all available qualifiers, see our documentation.
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
Implement pow(x, n), which calculates x raised to the power n (xn).
Example 1:
Input: 2.00000, 10 Output: 1024.00000 Example 2:
Input: 2.10000, 3 Output: 9.26100 Example 3:
Input: 2.00000, -2 Output: 0.25000 Explanation: 2-2 = 1/22 = 1/4 = 0.25 Note:
-100.0 < x < 100.0 n is a 32-bit signed integer, within the range [−231, 231 − 1]
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/powx-n 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
思路一:
The text was updated successfully, but these errors were encountered:
不好意思了,没注意把原来的issue内容给改掉了
Sorry, something went wrong.
@hey-monster I would like to work on this.
No branches or pull requests
Implement pow(x, n), which calculates x raised to the power n (xn).
Example 1:
Input: 2.00000, 10
Output: 1024.00000
Example 2:
Input: 2.10000, 3
Output: 9.26100
Example 3:
Input: 2.00000, -2
Output: 0.25000
Explanation: 2-2 = 1/22 = 1/4 = 0.25
Note:
-100.0 < x < 100.0
n is a 32-bit signed integer, within the range [−231, 231 − 1]
来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/powx-n
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
思路一:
The text was updated successfully, but these errors were encountered: