1684. Count the Number of Consistent Strings.py

class Solution:
    def countConsistentStrings(self, allowed: str, words: List[str]) -> int:
        allowed_set = set(allowed)  # Convert allowed string to a set for O(1) lookups
        consistent_count = 0
        
        for word in words:
            if all(char in allowed_set for char in word):
                consistent_count += 1
        
        return consistent_count