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6.c
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6.c
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char *convert(char *s, int nRows) {
int len = strlen(s);
char *ret = (char *)malloc(len + 1);
int i, j;
j = 0; /* index of return string */
/**
* don't know why return s or modify input pointer will cause runtime error,
* so I have to copy a string and try not to modify s. I tried 5 times to
* finally find out what happened, sad for my acceptance rate...
*/
if (nRows == 1) {
while (j < len) {
ret[j] = s[j];
j++;
}
ret[len] = '\0';
return ret;
}
int t = (nRows - 1) * 2;
int shift, offset;
for (i = 0; i < nRows; i++) {
offset = 0;
shift = (nRows - i - 1) * 2;
while (j < len && i + offset < len) {
ret[j] = s[i + offset];
j++;
if (shift == 0) {
shift = t;
}
offset += shift;
if (shift != t) {
shift = t - shift;
}
}
}
ret[len] = '\0';
return ret;
}
int main() {
char str1[] = "PAYPALISHIRING";
char str2[] = "A";
char str3[] = "zvmwnuufnnxvloyvgmliuqandlyavfauaosnlnv";
printf("%s\n", convert(str1, 3));
printf("%s\n", convert(str1, 4));
printf("%s\n", convert(str1, 5));
printf("%s\n", convert(str2, 1));
printf("%s\n", convert(str3, 1));
return 0;
}