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1345 Jump Game IV
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1345 Jump Game IV
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Given an array of integers arr, you are initially positioned at the first index of the array.
In one step you can jump from index i to index:
i + 1 where: i + 1 < arr.length.
i - 1 where: i - 1 >= 0.
j where: arr[i] == arr[j] and i != j.
Return the minimum number of steps to reach the last index of the array.
Notice that you can not jump outside of the array at any time.
Example 1:
Input: arr = [100,-23,-23,404,100,23,23,23,3,404]
Output: 3
Explanation: You need three jumps from index 0 --> 4 --> 3 --> 9. Note that index 9 is the last index of the array.
public int minJumps(int[] arr) {
if(arr.length==1)return 0;
int jump = 0;
int[] visited = new int[arr.length];
HashMap<Integer,List<Integer>> map = new HashMap();
for(int i=0;i<arr.length;i++){
if(map.containsKey(arr[i])){
map.get(arr[i]).add(i);
}else{
map.put(arr[i],new ArrayList());
map.get(arr[i]).add(i);
}
}
Queue<Integer> q = new ArrayDeque();
q.add(0);
visited[0]=1;
while(!q.isEmpty()){
int n = q.size();
for(int i=0;i<n;i++){
int index = q.poll();
if(index==arr.length-1)return jump;
if(index-1>=0 && index-1<arr.length && visited[index-1]==0){
q.add(index-1);
visited[index-1] =1;
}
if(index+1>=0 && index+1<arr.length && visited[index+1]==0){
q.add(index+1);
visited[index+1] =1;
}
if(map.containsKey(arr[index])){
for(int num : map.get(arr[index])){
q.add(num);
visited[num] =1;
}
map.remove(arr[index]);
}
}
jump++;
}
return jump;
}
}