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Consider a case where typeA is a supertype of typeB. In the type scope, we state that the minimum (note that this is not a problem for maximum) number of instances of these types are TypeA: 5 and TypeB:3. Currently, the program would output something like this: o1 | o2 | o3 | o4 | o5 => TypeA and o6 | o7 | o8 => TypeB, which is incorrect.
The correct output would be o1 | o2 | o3 | o4 | o5 => TypeA and o1 | o2 | o3 => TypeB.
Consider a case where typeA is a supertype of typeB. In the type scope, we state that the minimum (note that this is not a problem for maximum) number of instances of these types are TypeA: 5 and TypeB:3. Currently, the program would output something like this:
o1 | o2 | o3 | o4 | o5 => TypeA
ando6 | o7 | o8 => TypeB
, which is incorrect.The correct output would be
o1 | o2 | o3 | o4 | o5 => TypeA
ando1 | o2 | o3 => TypeB
.Refer to lines 35,36 and lines 63, 64, 73, 74 .
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