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xy to tikz: triangular commuting diagram of two monos
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favonia committed Feb 12, 2023
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Expand Up @@ -85,8 +85,18 @@ \subsection{Subgroups as monomorphisms}
\begin{lemma}
\label{lem:setofsubgroups}
Let $G$ be a group and $(H,i_H,!),(H',i_{H'},!):\typemono_G$ be two monomorphisms into $G$. The identity type $(H,i_H,!)\eqto{}(H',i_{H'},!)$ is equivalent to
\marginnote{$$\xymatrix{H\ar[rr]^f_\simeq\ar[dr]_{i_H}&&H'\ar[dl]^{i_{H'}}\\
&G&}$$}
\marginnote{
\[
\begin{tikzpicture}[scale=1.5]
\path (-1,0) node (H) {$H$}
(1,0) node (H') {$H'$}
(0,-1) node (G) {$G$};
\draw[->] (H) -- node[above] {$f$} node[below] {$\simeq$} (H');
\draw[->] (H) -- node[below left] {$i_H$} (G);
\draw[->] (H') -- node[below right] {$i_{H'}$} (G);
\end{tikzpicture}
\]
}
$$\sum_{f:\Hom(H,H')}\isEq(\US f)\times (i_{H'}\eqto{}i_H f)$$ and is a proposition.
In particular, the type $\typemono_G$ of monomorphisms into $G$ is a set.
\end{lemma}
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