Solution #1193
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Solution #1193
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EdAlekseiev
suggested changes
Jan 17, 2024
app/main.py
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| counter = 0 | ||
| for char in phrase: | ||
| if char.lower() == letter.lower(): | ||
| counter += 1 | ||
| return counter |
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Rewrite this function to one line with using method count of string
vburkalo
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Jan 17, 2024
EdAlekseiev
suggested changes
Jan 18, 2024
app/main.py
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| return phrase.lower().count(letter.lower()) | ||
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| print(count_occurrences("ABC", "a")) |
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