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Solution #1809

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Solution #1809

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YaYaYaroslav
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app/main.py Outdated
Comment on lines 17 to 22
count = 0
for char in phrase:
if char.lower() == letter.lower():
count += 1

return count
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not bad solution but try to make it in one line. You can use an already existing method that counts the appearance of a char in string, for example :)

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nice!

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4 participants