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Zipf: let n have type F #1518
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Zipf: let n have type F #1518
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You cannot use the continuous test, because the cdf is not continuous. It does work, if you replace |
This should be mostly ready, but do we want to make this change? Also note: #1517 added a note about casting results to ints being safe as a result of the input bounding the output; the input can now be larger too. |
I am not sure if we should do it. I do not have some quantitative proof for it, but I doubt that for values bigger Another point might be the name. If you search for Zipf, you fill find mostly the Zeta distribution, scipy has our Zipf as Zipfian. Maybe this would be a better name. Edit: I guess there is still a difference to Zeta, because even for |
I'll wait for @vks to comment. |
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Looks good, but I'm a bit confused why there is a test failure.
@@ -385,7 +385,7 @@ fn zipf() { | |||
let parameters = [(1000, 1.0), (500, 2.0), (1000, 0.5)]; | |||
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for (seed, (n, x)) in parameters.into_iter().enumerate() { | |||
let dist = rand_distr::Zipf::new(n, x).unwrap(); | |||
let dist = rand_distr::Zipf::new(n as f64, x).unwrap(); |
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You might as well change the values in parameters
to floats.
Which test failure? Do you have an opinion on the name? Zipf vs Zipfian |
CHANGELOG.md
entrySummary
Change the parameter type of Zipf's
n
toF
Motivation
#1323 (comment)
Details
The CDF test fails:
The value stability tests (only 4 samples; bottom of
zipf.rs
) did not fail.